-6x^2=-2000x

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Solution for -6x^2=-2000x equation:



-6x^2=-2000x
We move all terms to the left:
-6x^2-(-2000x)=0
We get rid of parentheses
-6x^2+2000x=0
a = -6; b = 2000; c = 0;
Δ = b2-4ac
Δ = 20002-4·(-6)·0
Δ = 4000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4000000}=2000$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2000)-2000}{2*-6}=\frac{-4000}{-12} =333+1/3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2000)+2000}{2*-6}=\frac{0}{-12} =0 $

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